3140131481 has 2 divisors, whose sum is σ = 3140131482. Its totient is φ = 3140131480.

The previous prime is 3140131417. The next prime is 3140131487. The reversal of 3140131481 is 1841310413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2389645456 + 750486025 = 48884^2 + 27395^2 .

It is an emirp because it is prime and its reverse (1841310413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3140131481 - 2⁶ = 3140131417 is a prime.

It is a super-2 number, since 2×3140131481² = 19720851435934506722, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3140131481.

It is not a weakly prime, because it can be changed into another prime (3140131487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570065740 + 1570065741.

It is an arithmetic number, because the mean of its divisors is an integer number (1570065741).

Almost surely, 2^3140131481 is an apocalyptic number.

It is an amenable number.

3140131481 is a deficient number, since it is larger than the sum of its proper divisors (1).

3140131481 is an equidigital number, since it uses as much as digits as its factorization.

3140131481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 26.

The square root of 3140131481 is about 56036.8760817375. The cubic root of 3140131481 is about 1464.3647890140.

Adding to 3140131481 its reverse (1841310413), we get a palindrome (4981441894).

The spelling of 3140131481 in words is "three billion, one hundred forty million, one hundred thirty-one thousand, four hundred eighty-one".