314014340113 has 4 divisors (see below), whose sum is σ = 316949053680. Its totient is φ = 311079626548.

The previous prime is 314014340069. The next prime is 314014340137. The reversal of 314014340113 is 311043410413.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311043410413 = 72937 ⋅4264549.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-314014340113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314014340713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1467356623 + ... + 1467356836.

It is an arithmetic number, because the mean of its divisors is an integer number (79237263420).

Almost surely, 2^314014340113 is an apocalyptic number.

It is an amenable number.

314014340113 is a deficient number, since it is larger than the sum of its proper divisors (2934713567).

314014340113 is a wasteful number, since it uses less digits than its factorization.

314014340113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2934713566.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 314014340113 its reverse (311043410413), we get a palindrome (625057750526).

The spelling of 314014340113 in words is "three hundred fourteen billion, fourteen million, three hundred forty thousand, one hundred thirteen".