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3140302021433 is a prime number
BaseRepresentation
bin101101101100101000100…
…101100010001100111001
3102010012200001021102201022
4231230220211202030321
5402422314304141213
610402345042432225
7442610416522253
oct55545045421471
912105601242638
103140302021433
111000881695005
12428740962675
1319a18ab49ab5
14abdc46a2cd3
1556a46c23308
hex2db28962339

3140302021433 has 2 divisors, whose sum is σ = 3140302021434. Its totient is φ = 3140302021432.

The previous prime is 3140302021393. The next prime is 3140302021447. The reversal of 3140302021433 is 3341202030413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3130323409984 + 9978611449 = 1769272^2 + 99893^2 .

It is a cyclic number.

It is not a de Polignac number, because 3140302021433 - 210 = 3140302020409 is a prime.

It is a super-3 number, since 3×31403020214333 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (3140302021133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570151010716 + 1570151010717.

It is an arithmetic number, because the mean of its divisors is an integer number (1570151010717).

Almost surely, 23140302021433 is an apocalyptic number.

It is an amenable number.

3140302021433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3140302021433 is an equidigital number, since it uses as much as digits as its factorization.

3140302021433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 3140302021433 its reverse (3341202030413), we get a palindrome (6481504051846).

The spelling of 3140302021433 in words is "three trillion, one hundred forty billion, three hundred two million, twenty-one thousand, four hundred thirty-three".