Base | Representation |
---|---|
bin | 11101001111110100… |
… | …110000110010100011 |
3 | 10000001121011121200111 |
4 | 131033310300302203 |
5 | 1003303411034332 |
6 | 22232104432151 |
7 | 2161135421335 |
oct | 351764606243 |
9 | 100047147614 |
10 | 31404002467 |
11 | 12355816952 |
12 | 6105178657 |
13 | 2c662155a6 |
14 | 173cabd455 |
15 | c3c00e947 |
hex | 74fd30ca3 |
31404002467 has 2 divisors, whose sum is σ = 31404002468. Its totient is φ = 31404002466.
The previous prime is 31404002431. The next prime is 31404002489. The reversal of 31404002467 is 76420040413.
It is a strong prime.
It is an emirp because it is prime and its reverse (76420040413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31404002467 - 215 = 31403969699 is a prime.
It is a super-2 number, since 2×314040024672 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31404002167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15702001233 + 15702001234.
It is an arithmetic number, because the mean of its divisors is an integer number (15702001234).
Almost surely, 231404002467 is an apocalyptic number.
31404002467 is a deficient number, since it is larger than the sum of its proper divisors (1).
31404002467 is an equidigital number, since it uses as much as digits as its factorization.
31404002467 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
The spelling of 31404002467 in words is "thirty-one billion, four hundred four million, two thousand, four hundred sixty-seven".
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