Base | Representation |
---|---|
bin | 101101101101011000110… |
… | …111011100010110000011 |
3 | 102010021202111102202011020 |
4 | 231231120313130112003 |
5 | 402430444134204103 |
6 | 10403001255520523 |
7 | 442636453441155 |
oct | 55553067342603 |
9 | 12107674382136 |
10 | 3141112022403 |
11 | 10011579367a3 |
12 | 428928089143 |
13 | 19a2898c1b04 |
14 | ac0600b2ad5 |
15 | 56a92dc3753 |
hex | 2db58ddc583 |
3141112022403 has 32 divisors (see below), whose sum is σ = 4220927884800. Its totient is φ = 2077743111936.
The previous prime is 3141112022303. The next prime is 3141112022417. The reversal of 3141112022403 is 3042202111413.
It is not a de Polignac number, because 3141112022403 - 210 = 3141112021379 is a prime.
It is a super-3 number, since 3×31411120224033 (a number of 38 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (3141112022003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 547515351 + ... + 547521087.
It is an arithmetic number, because the mean of its divisors is an integer number (131903996400).
Almost surely, 23141112022403 is an apocalyptic number.
3141112022403 is a deficient number, since it is larger than the sum of its proper divisors (1079815862397).
3141112022403 is a wasteful number, since it uses less digits than its factorization.
3141112022403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8011.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 3141112022403 its reverse (3042202111413), we get a palindrome (6183314133816).
The spelling of 3141112022403 in words is "three trillion, one hundred forty-one billion, one hundred twelve million, twenty-two thousand, four hundred three".
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