314111343111413 has 4 divisors (see below), whose sum is σ = 314449460812140. Its totient is φ = 313773225410688.

The previous prime is 314111343111299. The next prime is 314111343111443.

314111343111413 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 50252318898769 + 263859024212644 = 7088887^2 + 16243738^2 .

It is a cyclic number.

It is not a de Polignac number, because 314111343111413 - 2²² = 314111338917109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 314111343111413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314111343111443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169058848970 + ... + 169058850827.

It is an arithmetic number, because the mean of its divisors is an integer number (78612365203035).

Almost surely, 2^{314111343111413} is an apocalyptic number.

It is an amenable number.

314111343111413 is a deficient number, since it is larger than the sum of its proper divisors (338117700727).

314111343111413 is an equidigital number, since it uses as much as digits as its factorization.

314111343111413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 338117700726.

The product of its digits is 5184, while the sum is 32.

The spelling of 314111343111413 in words is "three hundred fourteen trillion, one hundred eleven billion, three hundred forty-three million, one hundred eleven thousand, four hundred thirteen".