314114131 has 2 divisors, whose sum is σ = 314114132. Its totient is φ = 314114130.

The previous prime is 314114107. The next prime is 314114147. The reversal of 314114131 is 131411413.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 314114131 - 2¹¹ = 314112083 is a prime.

It is a super-2 number, since 2×314114131² = 197335374587770322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 314114099 and 314114108.

It is not a weakly prime, because it can be changed into another prime (314114531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157057065 + 157057066.

It is an arithmetic number, because the mean of its divisors is an integer number (157057066).

Almost surely, 2^314114131 is an apocalyptic number.

314114131 is a deficient number, since it is larger than the sum of its proper divisors (1).

314114131 is an equidigital number, since it uses as much as digits as its factorization.

314114131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 19.

The square root of 314114131 is about 17723.2652465622. The cubic root of 314114131 is about 679.7707784208.

Adding to 314114131 its reverse (131411413), we get a palindrome (445525544).

The spelling of 314114131 in words is "three hundred fourteen million, one hundred fourteen thousand, one hundred thirty-one".