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31412102433 = 310470700811
BaseRepresentation
bin11101010000010011…
…101010010100100001
310000002011102010202020
4131100103222110201
51003312444234213
622232554212053
72161264315365
oct352023522441
9100064363666
1031412102433
111235a349538
126107a24029
132c67ac037a
14173dbcb2a5
15c3caae923
hex7504ea521

31412102433 has 4 divisors (see below), whose sum is σ = 41882803248. Its totient is φ = 20941401620.

The previous prime is 31412102413. The next prime is 31412102441. The reversal of 31412102433 is 33420121413.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31412102433 - 25 = 31412102401 is a prime.

It is a super-2 number, since 2×314121024332 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (31412102413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5235350403 + ... + 5235350408.

It is an arithmetic number, because the mean of its divisors is an integer number (10470700812).

Almost surely, 231412102433 is an apocalyptic number.

It is an amenable number.

31412102433 is a deficient number, since it is larger than the sum of its proper divisors (10470700815).

31412102433 is a wasteful number, since it uses less digits than its factorization.

31412102433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10470700814.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 31412102433 its reverse (33420121413), we get a palindrome (64832223846).

The spelling of 31412102433 in words is "thirty-one billion, four hundred twelve million, one hundred two thousand, four hundred thirty-three".

Divisors: 1 3 10470700811 31412102433