31414400441413 has 4 divisors (see below), whose sum is σ = 34270255027008. Its totient is φ = 28558545855820.

The previous prime is 31414400441401. The next prime is 31414400441507.

31414400441413 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31414400441413 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31414400441213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1427927292781 + ... + 1427927292802.

It is an arithmetic number, because the mean of its divisors is an integer number (8567563756752).

Almost surely, 2^{31414400441413} is an apocalyptic number.

It is an amenable number.

31414400441413 is a deficient number, since it is larger than the sum of its proper divisors (2855854585595).

31414400441413 is a wasteful number, since it uses less digits than its factorization.

31414400441413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2855854585594.

The product of its (nonzero) digits is 36864, while the sum is 34.

It can be divided in two parts, 31414400 and 441413, that added together give a palindrome (31855813).

The spelling of 31414400441413 in words is "thirty-one trillion, four hundred fourteen billion, four hundred million, four hundred forty-one thousand, four hundred thirteen".