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314211410081 is a prime number
BaseRepresentation
bin1001001001010000111…
…01011010000010100001
31010001000221012110102122
410210220131122002201
520122001110110311
6400202520554025
731462310626652
oct4445035320241
91101027173378
10314211410081
11111290171008
1250a90922915
132382618b3ba
14112ca72b529
1582901520db
hex492875a0a1

314211410081 has 2 divisors, whose sum is σ = 314211410082. Its totient is φ = 314211410080.

The previous prime is 314211410041. The next prime is 314211410129. The reversal of 314211410081 is 180014112413.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 313645921681 + 565488400 = 560041^2 + 23780^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-314211410081 is a prime.

It is a super-2 number, since 2×3142114100812 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 314211410081.

It is not a weakly prime, because it can be changed into another prime (314211410041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157105705040 + 157105705041.

It is an arithmetic number, because the mean of its divisors is an integer number (157105705041).

Almost surely, 2314211410081 is an apocalyptic number.

It is an amenable number.

314211410081 is a deficient number, since it is larger than the sum of its proper divisors (1).

314211410081 is an equidigital number, since it uses as much as digits as its factorization.

314211410081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 26.

Adding to 314211410081 its reverse (180014112413), we get a palindrome (494225522494).

The spelling of 314211410081 in words is "three hundred fourteen billion, two hundred eleven million, four hundred ten thousand, eighty-one".