Base | Representation |
---|---|
bin | 101101101110011100101… |
… | …100101011100111010001 |
3 | 102010101200210211122100101 |
4 | 231232130230223213101 |
5 | 402440312003131144 |
6 | 10403310231452401 |
7 | 443006612514643 |
oct | 55563454534721 |
9 | 12111623748311 |
10 | 3142250052049 |
11 | 1001691266269 |
12 | 428ba5227101 |
13 | 19a40b5c9534 |
14 | ac12b2b0893 |
15 | 56b0cc6c6d4 |
hex | 2db9cb2b9d1 |
3142250052049 has 2 divisors, whose sum is σ = 3142250052050. Its totient is φ = 3142250052048.
The previous prime is 3142250051981. The next prime is 3142250052083. The reversal of 3142250052049 is 9402500522413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3125488089025 + 16761963024 = 1767905^2 + 129468^2 .
It is a cyclic number.
It is not a de Polignac number, because 3142250052049 - 221 = 3142247954897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3142250051999 and 3142250052017.
It is not a weakly prime, because it can be changed into another prime (3142250052449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571125026024 + 1571125026025.
It is an arithmetic number, because the mean of its divisors is an integer number (1571125026025).
Almost surely, 23142250052049 is an apocalyptic number.
It is an amenable number.
3142250052049 is a deficient number, since it is larger than the sum of its proper divisors (1).
3142250052049 is an equidigital number, since it uses as much as digits as its factorization.
3142250052049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 3142250052049 in words is "three trillion, one hundred forty-two billion, two hundred fifty million, fifty-two thousand, forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •