Base | Representation |
---|---|
bin | 101101101110011100101… |
… | …100101011100111010011 |
3 | 102010101200210211122100110 |
4 | 231232130230223213103 |
5 | 402440312003131201 |
6 | 10403310231452403 |
7 | 443006612514645 |
oct | 55563454534723 |
9 | 12111623748313 |
10 | 3142250052051 |
11 | 1001691266270 |
12 | 428ba5227103 |
13 | 19a40b5c9536 |
14 | ac12b2b0895 |
15 | 56b0cc6c6d6 |
hex | 2db9cb2b9d3 |
3142250052051 has 16 divisors (see below), whose sum is σ = 4571446019328. Its totient is φ = 1904018767200.
The previous prime is 3142250052049. The next prime is 3142250052083. The reversal of 3142250052051 is 1502500522413.
It is not a de Polignac number, because 3142250052051 - 21 = 3142250052049 is a prime.
It is a super-2 number, since 2×31422500520512 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3142250052451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9210015 + ... + 9545096.
It is an arithmetic number, because the mean of its divisors is an integer number (285715376208).
Almost surely, 23142250052051 is an apocalyptic number.
3142250052051 is a deficient number, since it is larger than the sum of its proper divisors (1429195967277).
3142250052051 is a wasteful number, since it uses less digits than its factorization.
3142250052051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18760202.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 3142250052051 its reverse (1502500522413), we get a palindrome (4644750574464).
The spelling of 3142250052051 in words is "three trillion, one hundred forty-two billion, two hundred fifty million, fifty-two thousand, fifty-one".
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