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3142500433 = 53833112297
BaseRepresentation
bin1011101101001110…
…1100000001010001
322010000011120011221
42323103230001101
522413440003213
61235454405041
7140605545562
oct27323540121
98100146157
103142500433
1113729500a6
12738500781
133b1088a17
1421b4dc169
15135d4138d
hexbb4ec051

3142500433 has 16 divisors (see below), whose sum is σ = 3252203136. Its totient is φ = 3034944640.

The previous prime is 3142500379. The next prime is 3142500457. The reversal of 3142500433 is 3340052413.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3142500433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3142500398 and 3142500407.

It is not an unprimeable number, because it can be changed into a prime (3142500533) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1366941 + ... + 1369237.

It is an arithmetic number, because the mean of its divisors is an integer number (203262696).

Almost surely, 23142500433 is an apocalyptic number.

It is an amenable number.

3142500433 is a deficient number, since it is larger than the sum of its proper divisors (109702703).

3142500433 is a wasteful number, since it uses less digits than its factorization.

3142500433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2744.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 3142500433 is about 56058.0095347668. The cubic root of 3142500433 is about 1464.7329411044.

Adding to 3142500433 its reverse (3340052413), we get a palindrome (6482552846).

The spelling of 3142500433 in words is "three billion, one hundred forty-two million, five hundred thousand, four hundred thirty-three".

Divisors: 1 53 83 311 2297 4399 16483 25813 121741 190651 714367 1368089 10104503 37861451 59292461 3142500433