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3142505041537 is a prime number
BaseRepresentation
bin101101101110101011111…
…001011000111010000001
3102010102100120122110011111
4231232223321120322001
5402441322242312122
610403351421043321
7443016130060351
oct55565371307201
912112316573144
103142505041537
111001802197684
124290566b6541
1319a44c397ca4
14ac1530c8b61
1556b25339d77
hex2dbabe58e81

3142505041537 has 2 divisors, whose sum is σ = 3142505041538. Its totient is φ = 3142505041536.

The previous prime is 3142505041513. The next prime is 3142505041541. The reversal of 3142505041537 is 7351405052413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2268063108081 + 874441933456 = 1506009^2 + 935116^2 .

It is an emirp because it is prime and its reverse (7351405052413) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3142505041537 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3142505041537.

It is not a weakly prime, because it can be changed into another prime (3142505041547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571252520768 + 1571252520769.

It is an arithmetic number, because the mean of its divisors is an integer number (1571252520769).

Almost surely, 23142505041537 is an apocalyptic number.

It is an amenable number.

3142505041537 is a deficient number, since it is larger than the sum of its proper divisors (1).

3142505041537 is an equidigital number, since it uses as much as digits as its factorization.

3142505041537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252000, while the sum is 40.

The spelling of 3142505041537 in words is "three trillion, one hundred forty-two billion, five hundred five million, forty-one thousand, five hundred thirty-seven".