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314312134142011 is a prime number
BaseRepresentation
bin100011101110111010111111…
…1000110101010100000111011
31112012212221120001022211221211
41013131311333012222200323
5312144142222320021021
63032253000121143551
7123130205456441365
oct10735657706524073
91465787501284854
10314312134142011
1191171033693945
122b30396992abb7
131064c679058045
145788b07781d35
152650ea73373e1
hex11ddd7f1aa83b

314312134142011 has 2 divisors, whose sum is σ = 314312134142012. Its totient is φ = 314312134142010.

The previous prime is 314312134142003. The next prime is 314312134142053. The reversal of 314312134142011 is 110241431213413.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 314312134142011 - 23 = 314312134142003 is a prime.

It is not a weakly prime, because it can be changed into another prime (314312134142311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157156067071005 + 157156067071006.

It is an arithmetic number, because the mean of its divisors is an integer number (157156067071006).

Almost surely, 2314312134142011 is an apocalyptic number.

314312134142011 is a deficient number, since it is larger than the sum of its proper divisors (1).

314312134142011 is an equidigital number, since it uses as much as digits as its factorization.

314312134142011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 314312134142011 its reverse (110241431213413), we get a palindrome (424553565355424).

The spelling of 314312134142011 in words is "three hundred fourteen trillion, three hundred twelve billion, one hundred thirty-four million, one hundred forty-two thousand, eleven".