Base | Representation |
---|---|
bin | 1001001001011100111… |
… | …01111001010001111101 |
3 | 1010001021221212012001021 |
4 | 10210232131321101331 |
5 | 20122202410420331 |
6 | 400220521144141 |
7 | 31464643426015 |
oct | 4445635712175 |
9 | 1101257765037 |
10 | 314312201341 |
11 | 111332052a76 |
12 | 50aba62b051 |
13 | 2384101b0b8 |
14 | 112d9c86c45 |
15 | 8298e11211 |
hex | 492e77947d |
314312201341 has 4 divisors (see below), whose sum is σ = 330854948800. Its totient is φ = 297769453884.
The previous prime is 314312201317. The next prime is 314312201353. The reversal of 314312201341 is 143102213413.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 314312201341 - 27 = 314312201213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (314312201041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8271373701 + ... + 8271373738.
It is an arithmetic number, because the mean of its divisors is an integer number (82713737200).
Almost surely, 2314312201341 is an apocalyptic number.
It is an amenable number.
314312201341 is a deficient number, since it is larger than the sum of its proper divisors (16542747459).
314312201341 is a wasteful number, since it uses less digits than its factorization.
314312201341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16542747458.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 314312201341 its reverse (143102213413), we get a palindrome (457414414754).
The spelling of 314312201341 in words is "three hundred fourteen billion, three hundred twelve million, two hundred one thousand, three hundred forty-one".
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