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314312201341 = 1916542747439
BaseRepresentation
bin1001001001011100111…
…01111001010001111101
31010001021221212012001021
410210232131321101331
520122202410420331
6400220521144141
731464643426015
oct4445635712175
91101257765037
10314312201341
11111332052a76
1250aba62b051
132384101b0b8
14112d9c86c45
158298e11211
hex492e77947d

314312201341 has 4 divisors (see below), whose sum is σ = 330854948800. Its totient is φ = 297769453884.

The previous prime is 314312201317. The next prime is 314312201353. The reversal of 314312201341 is 143102213413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 314312201341 - 27 = 314312201213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314312201041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8271373701 + ... + 8271373738.

It is an arithmetic number, because the mean of its divisors is an integer number (82713737200).

Almost surely, 2314312201341 is an apocalyptic number.

It is an amenable number.

314312201341 is a deficient number, since it is larger than the sum of its proper divisors (16542747459).

314312201341 is a wasteful number, since it uses less digits than its factorization.

314312201341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16542747458.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 314312201341 its reverse (143102213413), we get a palindrome (457414414754).

The spelling of 314312201341 in words is "three hundred fourteen billion, three hundred twelve million, two hundred one thousand, three hundred forty-one".

Divisors: 1 19 16542747439 314312201341