Base | Representation |
---|---|
bin | 101101101111010010010… |
… | …110101011011111011011 |
3 | 102010111000112201122022222 |
4 | 231233102112223133123 |
5 | 402444132431112133 |
6 | 10403535430134255 |
7 | 443041123224362 |
oct | 55572226533733 |
9 | 12114015648288 |
10 | 3143150254043 |
11 | 1002003416358 |
12 | 4291b67b138b |
13 | 19a522c63b37 |
14 | ac1b4a807d9 |
15 | 56b61cd8e98 |
hex | 2dbd25ab7db |
3143150254043 has 2 divisors, whose sum is σ = 3143150254044. Its totient is φ = 3143150254042.
The previous prime is 3143150254039. The next prime is 3143150254063. The reversal of 3143150254043 is 3404520513413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3143150254043 - 22 = 3143150254039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3143150253994 and 3143150254012.
It is not a weakly prime, because it can be changed into another prime (3143150254063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571575127021 + 1571575127022.
It is an arithmetic number, because the mean of its divisors is an integer number (1571575127022).
Almost surely, 23143150254043 is an apocalyptic number.
3143150254043 is a deficient number, since it is larger than the sum of its proper divisors (1).
3143150254043 is an equidigital number, since it uses as much as digits as its factorization.
3143150254043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 3143150254043 its reverse (3404520513413), we get a palindrome (6547670767456).
The spelling of 3143150254043 in words is "three trillion, one hundred forty-three billion, one hundred fifty million, two hundred fifty-four thousand, forty-three".
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