314332513624142 has 12 divisors (see below), whose sum is σ = 510557840177040. Its totient is φ = 145076544749448.

The previous prime is 314332513624121. The next prime is 314332513624147. The reversal of 314332513624142 is 241426315233413.

It is a junction number, because it is equal to n+sod(n) for n = 314332513624093 and 314332513624102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314332513624147) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 464988925142 + ... + 464988925817.

It is an arithmetic number, because the mean of its divisors is an integer number (42546486681420).

Almost surely, 2^{314332513624142} is an apocalyptic number.

314332513624142 is a deficient number, since it is larger than the sum of its proper divisors (196225326552898).

314332513624142 is a wasteful number, since it uses less digits than its factorization.

314332513624142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 929977850987 (or 929977850974 counting only the distinct ones).

The product of its digits is 1244160, while the sum is 44.

Adding to 314332513624142 its reverse (241426315233413), we get a palindrome (555758828857555).

The spelling of 314332513624142 in words is "three hundred fourteen trillion, three hundred thirty-two billion, five hundred thirteen million, six hundred twenty-four thousand, one hundred forty-two".