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31434053354550 = 232527211129598241
BaseRepresentation
bin1110010010110110011111…
…00101011000010000110110
311010022001210020002012110200
413021123033211120100312
513110003420124321200
6150504334343301330
76423015100650300
oct711331745302066
9133261706065420
1031434053354550
11a01a11a6a8670
123638168a4a846
1314702ac0c0b52
147a95b8482970
15397a12826800
hex1c96cf958436

31434053354550 has 216 divisors, whose sum is σ = 107172043811352. Its totient is φ = 6531751296000.

The previous prime is 31434053354537. The next prime is 31434053354563. The reversal of 31434053354550 is 5545335043413.

31434053354550 is a `hidden beast` number, since 3 + 1 + 4 + 3 + 4 + 0 + 53 + 3 + 545 + 50 = 666.

It is an interprime number because it is at equal distance from previous prime (31434053354537) and next prime (31434053354563).

It is a super-2 number, since 2×314340533545502 (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a junction number, because it is equal to n+sod(n) for n = 31434053354496 and 31434053354505.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 64556571 + ... + 65041670.

It is an arithmetic number, because the mean of its divisors is an integer number (496166869497).

Almost surely, 231434053354550 is an apocalyptic number.

31434053354550 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

31434053354550 is an abundant number, since it is smaller than the sum of its proper divisors (75737990456802).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31434053354550 is a wasteful number, since it uses less digits than its factorization.

31434053354550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129598284 (or 129598269 counting only the distinct ones).

The product of its (nonzero) digits is 3240000, while the sum is 45.

Adding to 31434053354550 its reverse (5545335043413), we get a palindrome (36979388397963).

The spelling of 31434053354550 in words is "thirty-one trillion, four hundred thirty-four billion, fifty-three million, three hundred fifty-four thousand, five hundred fifty".