Base | Representation |
---|---|
bin | 1011101101011100… |
… | …1100111000101001 |
3 | 22010001220100121211 |
4 | 2323113030320221 |
5 | 22414203441411 |
6 | 1235530233121 |
7 | 140616433054 |
oct | 27327147051 |
9 | 8101810554 |
10 | 3143421481 |
11 | 137341a0a2 |
12 | 7388857a1 |
13 | 3b131c015 |
14 | 21b69ba9b |
15 | 135e74221 |
hex | bb5cce29 |
3143421481 has 2 divisors, whose sum is σ = 3143421482. Its totient is φ = 3143421480.
The previous prime is 3143421473. The next prime is 3143421509. The reversal of 3143421481 is 1841243413.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3142611481 + 810000 = 56059^2 + 900^2 .
It is a cyclic number.
It is not a de Polignac number, because 3143421481 - 23 = 3143421473 is a prime.
It is a super-2 number, since 2×31434214812 = 19762197214424466722, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3143427481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571710740 + 1571710741.
It is an arithmetic number, because the mean of its divisors is an integer number (1571710741).
Almost surely, 23143421481 is an apocalyptic number.
It is an amenable number.
3143421481 is a deficient number, since it is larger than the sum of its proper divisors (1).
3143421481 is an equidigital number, since it uses as much as digits as its factorization.
3143421481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9216, while the sum is 31.
The square root of 3143421481 is about 56066.2240658313. The cubic root of 3143421481 is about 1464.8760286015.
Adding to 3143421481 its reverse (1841243413), we get a palindrome (4984664894).
The spelling of 3143421481 in words is "three billion, one hundred forty-three million, four hundred twenty-one thousand, four hundred eighty-one".
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