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314344502441 = 476688180903
BaseRepresentation
bin1001001001100000110…
…01000111010010101001
31010001101012122020211022
410210300121013102221
520122234143034231
6400224033342225
731465515120224
oct4446031072251
91101335566738
10314344502441
111113493052a2
1250b09407975
132384791a588
14113002945bb
15829bb91c7b
hex49306474a9

314344502441 has 4 divisors (see below), whose sum is σ = 321032683392. Its totient is φ = 307656321492.

The previous prime is 314344502413. The next prime is 314344502449. The reversal of 314344502441 is 144205443413.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-314344502441 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (314344502449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3344090405 + ... + 3344090498.

It is an arithmetic number, because the mean of its divisors is an integer number (80258170848).

Almost surely, 2314344502441 is an apocalyptic number.

It is an amenable number.

314344502441 is a deficient number, since it is larger than the sum of its proper divisors (6688180951).

314344502441 is an equidigital number, since it uses as much as digits as its factorization.

314344502441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6688180950.

The product of its (nonzero) digits is 92160, while the sum is 35.

Adding to 314344502441 its reverse (144205443413), we get a palindrome (458549945854).

The spelling of 314344502441 in words is "three hundred fourteen billion, three hundred forty-four million, five hundred two thousand, four hundred forty-one".

Divisors: 1 47 6688180903 314344502441