Base | Representation |
---|---|
bin | 1110010010110111011101… |
… | …01100100110000111100011 |
3 | 11010022010010121021210220020 |
4 | 13021123232230212013203 |
5 | 13110011002241340003 |
6 | 150504502231244523 |
7 | 6423034036522623 |
oct | 711335654460743 |
9 | 133263117253806 |
10 | 31434575340003 |
11 | a01a368311000 |
12 | 3638293819743 |
13 | 14703632a2c94 |
14 | 7a962791c883 |
15 | 397a43583d53 |
hex | 1c96eeb261e3 |
31434575340003 has 64 divisors (see below), whose sum is σ = 48952613606400. Its totient is φ = 17879205020160.
The previous prime is 31434575340001. The next prime is 31434575340017. The reversal of 31434575340003 is 30004357543413.
It is not a de Polignac number, because 31434575340003 - 21 = 31434575340001 is a prime.
It is a super-3 number, since 3×314345753400033 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (31434575340001) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23027026 + ... + 24353912.
It is an arithmetic number, because the mean of its divisors is an integer number (764884587600).
Almost surely, 231434575340003 is an apocalyptic number.
31434575340003 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
31434575340003 is a deficient number, since it is larger than the sum of its proper divisors (17518038266397).
31434575340003 is a wasteful number, since it uses less digits than its factorization.
31434575340003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1327289 (or 1327267 counting only the distinct ones).
The product of its (nonzero) digits is 907200, while the sum is 42.
The spelling of 31434575340003 in words is "thirty-one trillion, four hundred thirty-four billion, five hundred seventy-five million, three hundred forty thousand, three".
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