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31435532541113 is a prime number
BaseRepresentation
bin1110010010111001001111…
…10000000001110010111001
311010022012121022102122222012
413021130213300001302321
513110014432312303423
6150505141223335305
76423066541560461
oct711344760016271
9133265538378865
1031435532541113
11a01a8096623a8
1236385002b1535
1314704866a667c
147a96b8ac8ba1
15397a9c60e078
hex1c9727c01cb9

31435532541113 has 2 divisors, whose sum is σ = 31435532541114. Its totient is φ = 31435532541112.

The previous prime is 31435532541041. The next prime is 31435532541139. The reversal of 31435532541113 is 31114523553413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31416159520144 + 19373020969 = 5605012^2 + 139187^2 .

It is a cyclic number.

It is not a de Polignac number, because 31435532541113 - 216 = 31435532475577 is a prime.

It is a super-2 number, since 2×314355325411132 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31435532541173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15717766270556 + 15717766270557.

It is an arithmetic number, because the mean of its divisors is an integer number (15717766270557).

Almost surely, 231435532541113 is an apocalyptic number.

It is an amenable number.

31435532541113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31435532541113 is an equidigital number, since it uses as much as digits as its factorization.

31435532541113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 324000, while the sum is 41.

The spelling of 31435532541113 in words is "thirty-one trillion, four hundred thirty-five billion, five hundred thirty-two million, five hundred forty-one thousand, one hundred thirteen".