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314430212434361 is a prime number
BaseRepresentation
bin100011101111110001111110…
…1000111100110100110111001
31112020022020100010110121010212
41013133203331013212212321
5312203111033340344421
63032423125004520505
7123141555532403522
oct10737437507464671
91466266303417125
10314430212434361
1191207116816621
122b322821b50135
131065a84607b09a
1457907097ad849
1526540b8742e5b
hex11df8fd1e69b9

314430212434361 has 2 divisors, whose sum is σ = 314430212434362. Its totient is φ = 314430212434360.

The previous prime is 314430212434333. The next prime is 314430212434369. The reversal of 314430212434361 is 163434212034413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 235109475558400 + 79320736875961 = 15333280^2 + 8906219^2 .

It is an emirp because it is prime and its reverse (163434212034413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314430212434361 - 26 = 314430212434297 is a prime.

It is not a weakly prime, because it can be changed into another prime (314430212434369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157215106217180 + 157215106217181.

It is an arithmetic number, because the mean of its divisors is an integer number (157215106217181).

Almost surely, 2314430212434361 is an apocalyptic number.

It is an amenable number.

314430212434361 is a deficient number, since it is larger than the sum of its proper divisors (1).

314430212434361 is an equidigital number, since it uses as much as digits as its factorization.

314430212434361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 497664, while the sum is 41.

Adding to 314430212434361 its reverse (163434212034413), we get a palindrome (477864424468774).

The spelling of 314430212434361 in words is "three hundred fourteen trillion, four hundred thirty billion, two hundred twelve million, four hundred thirty-four thousand, three hundred sixty-one".