Base | Representation |
---|---|
bin | 1110010011000111011000… |
… | …00000000010100010111001 |
3 | 11010022221012002122112212222 |
4 | 13021203230000002202321 |
5 | 13110131002212240441 |
6 | 150512434150013425 |
7 | 6423455553342026 |
oct | 711435400024271 |
9 | 133287162575788 |
10 | 31443120040121 |
11 | a022a525a6739 |
12 | 3639a79347275 |
13 | 14710c561c15a |
14 | 7a9bd869654d |
15 | 397d937c6d4b |
hex | 1c98ec0028b9 |
31443120040121 has 2 divisors, whose sum is σ = 31443120040122. Its totient is φ = 31443120040120.
The previous prime is 31443120040001. The next prime is 31443120040139. The reversal of 31443120040121 is 12104002134413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18662495040121 + 12780625000000 = 4320011^2 + 3575000^2 .
It is a cyclic number.
It is not a de Polignac number, because 31443120040121 - 218 = 31443119777977 is a prime.
It is not a weakly prime, because it can be changed into another prime (31443120040151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15721560020060 + 15721560020061.
It is an arithmetic number, because the mean of its divisors is an integer number (15721560020061).
Almost surely, 231443120040121 is an apocalyptic number.
It is an amenable number.
31443120040121 is a deficient number, since it is larger than the sum of its proper divisors (1).
31443120040121 is an equidigital number, since it uses as much as digits as its factorization.
31443120040121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 31443120040121 its reverse (12104002134413), we get a palindrome (43547122174534).
The spelling of 31443120040121 in words is "thirty-one trillion, four hundred forty-three billion, one hundred twenty million, forty thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •