Base | Representation |
---|---|
bin | 1110010011001000000101… |
… | …10010110101100011011101 |
3 | 11010022222011202020020111012 |
4 | 13021210002302311203131 |
5 | 13110132243112030010 |
6 | 150512540130305005 |
7 | 6423501205663154 |
oct | 711440262654335 |
9 | 133288152206435 |
10 | 31443502455005 |
11 | a0231294506a3 |
12 | 3639b65428165 |
13 | 1471156914554 |
14 | 7a9c333a059b |
15 | 397db7165005 |
hex | 1c9902cb58dd |
31443502455005 has 32 divisors (see below), whose sum is σ = 39091114395360. Its totient is φ = 24251437808640.
The previous prime is 31443502454999. The next prime is 31443502455047. The reversal of 31443502455005 is 50055420534413.
It can be written as a sum of positive squares in 16 ways, for example, as 6566770130041 + 24876732324964 = 2562571^2 + 4987658^2 .
It is not a de Polignac number, because 31443502455005 - 230 = 31442428713181 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1748698115 + ... + 1748716095.
It is an arithmetic number, because the mean of its divisors is an integer number (1221597324855).
Almost surely, 231443502455005 is an apocalyptic number.
It is an amenable number.
31443502455005 is a deficient number, since it is larger than the sum of its proper divisors (7647611940355).
31443502455005 is a wasteful number, since it uses less digits than its factorization.
31443502455005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35201.
The product of its (nonzero) digits is 720000, while the sum is 41.
Adding to 31443502455005 its reverse (50055420534413), we get a palindrome (81498922989418).
The spelling of 31443502455005 in words is "thirty-one trillion, four hundred forty-three billion, five hundred two million, four hundred fifty-five thousand, five".
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