3145004431 has 4 divisors (see below), whose sum is σ = 3310531000. Its totient is φ = 2979477864.

The previous prime is 3145004413. The next prime is 3145004459. The reversal of 3145004431 is 1344005413.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1344005413 = 19 ⋅70737127.

It is a cyclic number.

It is not a de Polignac number, because 3145004431 - 2⁵ = 3145004399 is a prime.

It is a super-2 number, since 2×3145004431² = 19782105742019267522, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3145004396 and 3145004405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3145004461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82763256 + ... + 82763293.

It is an arithmetic number, because the mean of its divisors is an integer number (827632750).

Almost surely, 2^3145004431 is an apocalyptic number.

3145004431 is a deficient number, since it is larger than the sum of its proper divisors (165526569).

3145004431 is a wasteful number, since it uses less digits than its factorization.

3145004431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165526568.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 3145004431 is about 56080.3390770776. The cubic root of 3145004431 is about 1465.1218792240.

Adding to 3145004431 its reverse (1344005413), we get a palindrome (4489009844).

The spelling of 3145004431 in words is "three billion, one hundred forty-five million, four thousand, four hundred thirty-one".