Base | Representation |
---|---|
bin | 11101010010100101… |
… | …111000101011000001 |
3 | 10000011211112121002211 |
4 | 131102211320223001 |
5 | 1003402302343431 |
6 | 22240443542121 |
7 | 2162241165052 |
oct | 352245705301 |
9 | 100154477084 |
10 | 31450434241 |
11 | 12379a4a816 |
12 | 611882a941 |
13 | 2c72a21805 |
14 | 1744d28729 |
15 | c411322b1 |
hex | 752978ac1 |
31450434241 has 2 divisors, whose sum is σ = 31450434242. Its totient is φ = 31450434240.
The previous prime is 31450434233. The next prime is 31450434293. The reversal of 31450434241 is 14243405413.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18082449841 + 13367984400 = 134471^2 + 115620^2 .
It is a cyclic number.
It is not a de Polignac number, because 31450434241 - 23 = 31450434233 is a prime.
It is not a weakly prime, because it can be changed into another prime (31450435241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15725217120 + 15725217121.
It is an arithmetic number, because the mean of its divisors is an integer number (15725217121).
Almost surely, 231450434241 is an apocalyptic number.
It is an amenable number.
31450434241 is a deficient number, since it is larger than the sum of its proper divisors (1).
31450434241 is an equidigital number, since it uses as much as digits as its factorization.
31450434241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 31450434241 its reverse (14243405413), we get a palindrome (45693839654).
The spelling of 31450434241 in words is "thirty-one billion, four hundred fifty million, four hundred thirty-four thousand, two hundred forty-one".
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