Base | Representation |
---|---|
bin | 1110010011010110110110… |
… | …11001011100100100010011 |
3 | 11010100201122022222111201212 |
4 | 13021223123121130210103 |
5 | 13110300012421002402 |
6 | 150520331011450335 |
7 | 6424201535045525 |
oct | 711533331344423 |
9 | 133321568874655 |
10 | 31451431422227 |
11 | a026528112073 |
12 | 363b5b88b69ab |
13 | 1471b1b516a2b |
14 | 7aa386457a15 |
15 | 3981cd2cd952 |
hex | 1c9adb65c913 |
31451431422227 has 2 divisors, whose sum is σ = 31451431422228. Its totient is φ = 31451431422226.
The previous prime is 31451431422181. The next prime is 31451431422239. The reversal of 31451431422227 is 72222413415413.
It is a strong prime.
It is an emirp because it is prime and its reverse (72222413415413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31451431422227 - 212 = 31451431418131 is a prime.
It is a super-3 number, since 3×314514314222273 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (31451431422127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15725715711113 + 15725715711114.
It is an arithmetic number, because the mean of its divisors is an integer number (15725715711114).
Almost surely, 231451431422227 is an apocalyptic number.
31451431422227 is a deficient number, since it is larger than the sum of its proper divisors (1).
31451431422227 is an equidigital number, since it uses as much as digits as its factorization.
31451431422227 is an evil number, because the sum of its binary digits is even.
The product of its digits is 322560, while the sum is 41.
The spelling of 31451431422227 in words is "thirty-one trillion, four hundred fifty-one billion, four hundred thirty-one million, four hundred twenty-two thousand, two hundred twenty-seven".
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