31452025413 has 4 divisors (see below), whose sum is σ = 41936033888. Its totient is φ = 20968016940.

The previous prime is 31452025391. The next prime is 31452025433.

31452025413 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 31452025413 - 2¹³ = 31452017221 is a prime.

It is a super-3 number, since 3×31452025413³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31452025433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5242004233 + ... + 5242004238.

It is an arithmetic number, because the mean of its divisors is an integer number (10484008472).

Almost surely, 2^31452025413 is an apocalyptic number.

It is an amenable number.

31452025413 is a deficient number, since it is larger than the sum of its proper divisors (10484008475).

31452025413 is a wasteful number, since it uses less digits than its factorization.

31452025413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10484008474.

The product of its (nonzero) digits is 14400, while the sum is 30.

It can be divided in two parts, 314520 and 25413, that added together give a palindrome (339933).

The spelling of 31452025413 in words is "thirty-one billion, four hundred fifty-two million, twenty-five thousand, four hundred thirteen".