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3145312135393 is a prime number
BaseRepresentation
bin101101110001010011001…
…101100110100011100001
3102010200121012200121000121
4231301103031212203201
5403013044401313033
610404534134520241
7443145524012431
oct55612315464341
912120535617017
103145312135393
111002a1277a85a
124296ba806081
1319a7a8b0a07c
14ac33bc382c1
1556c3b9c662d
hex2dc533668e1

3145312135393 has 2 divisors, whose sum is σ = 3145312135394. Its totient is φ = 3145312135392.

The previous prime is 3145312135337. The next prime is 3145312135451. The reversal of 3145312135393 is 3935312135413.

3145312135393 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2679713342289 + 465598793104 = 1636983^2 + 682348^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3145312135393 is a prime.

It is not a weakly prime, because it can be changed into another prime (3145312135193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572656067696 + 1572656067697.

It is an arithmetic number, because the mean of its divisors is an integer number (1572656067697).

Almost surely, 23145312135393 is an apocalyptic number.

It is an amenable number.

3145312135393 is a deficient number, since it is larger than the sum of its proper divisors (1).

3145312135393 is an equidigital number, since it uses as much as digits as its factorization.

3145312135393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 437400, while the sum is 43.

The spelling of 3145312135393 in words is "three trillion, one hundred forty-five billion, three hundred twelve million, one hundred thirty-five thousand, three hundred ninety-three".