Base | Representation |
---|---|
bin | 1001001001111001111… |
… | …01000001101101101011 |
3 | 1010001220220012000000221 |
4 | 10210330331001231223 |
5 | 20123202120241441 |
6 | 400301002310511 |
7 | 31503654311245 |
oct | 4447475015553 |
9 | 1101826160027 |
10 | 314555243371 |
11 | 111447264056 |
12 | 50b67ab8437 |
13 | 2387c495755 |
14 | 11320271095 |
15 | 82b041d8d1 |
hex | 493cf41b6b |
314555243371 has 2 divisors, whose sum is σ = 314555243372. Its totient is φ = 314555243370.
The previous prime is 314555243131. The next prime is 314555243419. The reversal of 314555243371 is 173342555413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 314555243371 - 215 = 314555210603 is a prime.
It is a super-2 number, since 2×3145552433712 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (314555247371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157277621685 + 157277621686.
It is an arithmetic number, because the mean of its divisors is an integer number (157277621686).
Almost surely, 2314555243371 is an apocalyptic number.
314555243371 is a deficient number, since it is larger than the sum of its proper divisors (1).
314555243371 is an equidigital number, since it uses as much as digits as its factorization.
314555243371 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 756000, while the sum is 43.
Adding to 314555243371 its reverse (173342555413), we get a palindrome (487897798784).
The spelling of 314555243371 in words is "three hundred fourteen billion, five hundred fifty-five million, two hundred forty-three thousand, three hundred seventy-one".
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