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31464046153 is a prime number
BaseRepresentation
bin11101010011011001…
…110011111001001001
310000012210011011010201
4131103121303321021
51003414243434103
622242051412201
72162464656661
oct352331637111
9100183134121
1031464046153
11123866a7631
1261212b4061
132c757a93b7
141746a6d1a1
15c4242051d
hex753673e49

31464046153 has 2 divisors, whose sum is σ = 31464046154. Its totient is φ = 31464046152.

The previous prime is 31464046121. The next prime is 31464046157. The reversal of 31464046153 is 35164046413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30696091209 + 767954944 = 175203^2 + 27712^2 .

It is an emirp because it is prime and its reverse (35164046413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31464046153 - 25 = 31464046121 is a prime.

It is a super-2 number, since 2×314640461532 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (31464046157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15732023076 + 15732023077.

It is an arithmetic number, because the mean of its divisors is an integer number (15732023077).

Almost surely, 231464046153 is an apocalyptic number.

It is an amenable number.

31464046153 is a deficient number, since it is larger than the sum of its proper divisors (1).

31464046153 is an equidigital number, since it uses as much as digits as its factorization.

31464046153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 37.

The spelling of 31464046153 in words is "thirty-one billion, four hundred sixty-four million, forty-six thousand, one hundred fifty-three".