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3147154413049 is a prime number
BaseRepresentation
bin101101110011000001000…
…001010101010111111001
3102010212100121020222212101
4231303001001111113321
5403030333012204144
610405441025143401
7443242264062343
oct55630101252771
912125317228771
103147154413049
111003778690279
12429b3378ab61
1319aa106b05aa
14ac474798293
1556ce85d16d4
hex2dcc10555f9

3147154413049 has 2 divisors, whose sum is σ = 3147154413050. Its totient is φ = 3147154413048.

The previous prime is 3147154412999. The next prime is 3147154413083. The reversal of 3147154413049 is 9403144517413.

3147154413049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3091407897600 + 55746515449 = 1758240^2 + 236107^2 .

It is an emirp because it is prime and its reverse (9403144517413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3147154413049 - 221 = 3147152315897 is a prime.

It is not a weakly prime, because it can be changed into another prime (3147194413049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1573577206524 + 1573577206525.

It is an arithmetic number, because the mean of its divisors is an integer number (1573577206525).

Almost surely, 23147154413049 is an apocalyptic number.

It is an amenable number.

3147154413049 is a deficient number, since it is larger than the sum of its proper divisors (1).

3147154413049 is an equidigital number, since it uses as much as digits as its factorization.

3147154413049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 725760, while the sum is 46.

The spelling of 3147154413049 in words is "three trillion, one hundred forty-seven billion, one hundred fifty-four million, four hundred thirteen thousand, forty-nine".