Base | Representation |
---|---|
bin | 1001001010100001000… |
… | …00010010011101001001 |
3 | 1010002202202101200011001 |
4 | 10211100200102131021 |
5 | 20124340103112324 |
6 | 400353320535001 |
7 | 31515046332565 |
oct | 4452040223511 |
9 | 1102682350131 |
10 | 314883254089 |
11 | 1115a542a398 |
12 | 51039921461 |
13 | 2390241cc31 |
14 | 11351a566a5 |
15 | 82ce111e44 |
hex | 4950812749 |
314883254089 has 2 divisors, whose sum is σ = 314883254090. Its totient is φ = 314883254088.
The previous prime is 314883254083. The next prime is 314883254107. The reversal of 314883254089 is 980452388413.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 204448665600 + 110434588489 = 452160^2 + 332317^2 .
It is an emirp because it is prime and its reverse (980452388413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 314883254089 - 25 = 314883254057 is a prime.
It is not a weakly prime, because it can be changed into another prime (314883254083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157441627044 + 157441627045.
It is an arithmetic number, because the mean of its divisors is an integer number (157441627045).
Almost surely, 2314883254089 is an apocalyptic number.
It is an amenable number.
314883254089 is a deficient number, since it is larger than the sum of its proper divisors (1).
314883254089 is an equidigital number, since it uses as much as digits as its factorization.
314883254089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6635520, while the sum is 55.
The spelling of 314883254089 in words is "three hundred fourteen billion, eight hundred eighty-three million, two hundred fifty-four thousand, eighty-nine".
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