314965081 has 2 divisors, whose sum is σ = 314965082. Its totient is φ = 314965080.

The previous prime is 314965051. The next prime is 314965087. The reversal of 314965081 is 180569413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 276723225 + 38241856 = 16635^2 + 6184^2 .

It is an emirp because it is prime and its reverse (180569413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314965081 - 2¹⁵ = 314932313 is a prime.

It is a super-2 number, since 2×314965081² = 198406004498673122, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 314965081.

It is not a weakly prime, because it can be changed into another prime (314965087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157482540 + 157482541.

It is an arithmetic number, because the mean of its divisors is an integer number (157482541).

Almost surely, 2^314965081 is an apocalyptic number.

It is an amenable number.

314965081 is a deficient number, since it is larger than the sum of its proper divisors (1).

314965081 is an equidigital number, since it uses as much as digits as its factorization.

314965081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 37.

The square root of 314965081 is about 17747.2555906540. The cubic root of 314965081 is about 680.3840686459.

The spelling of 314965081 in words is "three hundred fourteen million, nine hundred sixty-five thousand, eighty-one".