Base | Representation |
---|---|
bin | 10010110001100… |
… | …001011110001001 |
3 | 210221200020102011 |
4 | 102301201132021 |
5 | 1121113101131 |
6 | 51130535521 |
7 | 10543134556 |
oct | 2261413611 |
9 | 727606364 |
10 | 314972041 |
11 | 15188017a |
12 | 895975a1 |
13 | 503407b7 |
14 | 2db8da2d |
15 | 1c9ba0b1 |
hex | 12c61789 |
314972041 has 2 divisors, whose sum is σ = 314972042. Its totient is φ = 314972040.
The previous prime is 314972027. The next prime is 314972069. The reversal of 314972041 is 140279413.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 249766416 + 65205625 = 15804^2 + 8075^2 .
It is a cyclic number.
It is not a de Polignac number, because 314972041 - 213 = 314963849 is a prime.
It is a super-2 number, since 2×3149720412 = 198414773223411362, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 314971994 and 314972012.
It is not a weakly prime, because it can be changed into another prime (314970041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157486020 + 157486021.
It is an arithmetic number, because the mean of its divisors is an integer number (157486021).
Almost surely, 2314972041 is an apocalyptic number.
It is an amenable number.
314972041 is a deficient number, since it is larger than the sum of its proper divisors (1).
314972041 is an equidigital number, since it uses as much as digits as its factorization.
314972041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
The square root of 314972041 is about 17747.4516762266. The cubic root of 314972041 is about 680.3890802472.
The spelling of 314972041 in words is "three hundred fourteen million, nine hundred seventy-two thousand, forty-one".
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