Base | Representation |
---|---|
bin | 101101110101101110100… |
… | …000110101111100001001 |
3 | 102011010212110021210122001 |
4 | 231311232200311330021 |
5 | 403102313133200043 |
6 | 10411041524031001 |
7 | 443404356553324 |
oct | 55655640657411 |
9 | 12133773253561 |
10 | 3150065131273 |
11 | 1004a3170aa25 |
12 | 42a606532461 |
13 | 19b085734a78 |
14 | ac66d19d7bb |
15 | 56e18ddb74d |
hex | 2dd6e835f09 |
3150065131273 has 2 divisors, whose sum is σ = 3150065131274. Its totient is φ = 3150065131272.
The previous prime is 3150065131247. The next prime is 3150065131309. The reversal of 3150065131273 is 3721315600513.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3147547901689 + 2517229584 = 1774133^2 + 50172^2 .
It is a cyclic number.
It is not a de Polignac number, because 3150065131273 - 233 = 3141475196681 is a prime.
It is not a weakly prime, because it can be changed into another prime (3150065131973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575032565636 + 1575032565637.
It is an arithmetic number, because the mean of its divisors is an integer number (1575032565637).
Almost surely, 23150065131273 is an apocalyptic number.
It is an amenable number.
3150065131273 is a deficient number, since it is larger than the sum of its proper divisors (1).
3150065131273 is an equidigital number, since it uses as much as digits as its factorization.
3150065131273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56700, while the sum is 37.
The spelling of 3150065131273 in words is "three trillion, one hundred fifty billion, sixty-five million, one hundred thirty-one thousand, two hundred seventy-three".
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