Base | Representation |
---|---|
bin | 1011101111000100… |
… | …1101110011101001 |
3 | 22010112201211020122 |
4 | 2323301031303221 |
5 | 22422430203001 |
6 | 1240332333025 |
7 | 141031415045 |
oct | 27361156351 |
9 | 8115654218 |
10 | 3150241001 |
11 | 1377257766 |
12 | 73b014175 |
13 | 3b286903b |
14 | 21c555025 |
15 | 13686eb1b |
hex | bbc4dce9 |
3150241001 has 2 divisors, whose sum is σ = 3150241002. Its totient is φ = 3150241000.
The previous prime is 3150240997. The next prime is 3150241037. The reversal of 3150241001 is 1001420513.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3141714601 + 8526400 = 56051^2 + 2920^2 .
It is a cyclic number.
It is not a de Polignac number, because 3150241001 - 22 = 3150240997 is a prime.
It is not a weakly prime, because it can be changed into another prime (3150241091) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575120500 + 1575120501.
It is an arithmetic number, because the mean of its divisors is an integer number (1575120501).
Almost surely, 23150241001 is an apocalyptic number.
It is an amenable number.
3150241001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3150241001 is an equidigital number, since it uses as much as digits as its factorization.
3150241001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 17.
The square root of 3150241001 is about 56127.0077680968. The cubic root of 3150241001 is about 1465.9345923369.
Adding to 3150241001 its reverse (1001420513), we get a palindrome (4151661514).
The spelling of 3150241001 in words is "three billion, one hundred fifty million, two hundred forty-one thousand, one".
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