Base | Representation |
---|---|
bin | 1001001010110010110… |
… | …01010010001101100011 |
3 | 1010010011011001201202011 |
4 | 10211121121102031203 |
5 | 20130141244204102 |
6 | 400420205533351 |
7 | 31521540220363 |
oct | 4453131221543 |
9 | 1103134051664 |
10 | 315032413027 |
11 | 111671647742 |
12 | 5107b874257 |
13 | 239272b6067 |
14 | 113677a29a3 |
15 | 82dc2772d7 |
hex | 4959652363 |
315032413027 has 2 divisors, whose sum is σ = 315032413028. Its totient is φ = 315032413026.
The previous prime is 315032412991. The next prime is 315032413039. The reversal of 315032413027 is 720314230513.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 315032413027 - 27 = 315032412899 is a prime.
It is a super-2 number, since 2×3150324130272 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 315032413027.
It is not a weakly prime, because it can be changed into another prime (315032417027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157516206513 + 157516206514.
It is an arithmetic number, because the mean of its divisors is an integer number (157516206514).
Almost surely, 2315032413027 is an apocalyptic number.
315032413027 is a deficient number, since it is larger than the sum of its proper divisors (1).
315032413027 is an equidigital number, since it uses as much as digits as its factorization.
315032413027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
The spelling of 315032413027 in words is "three hundred fifteen billion, thirty-two million, four hundred thirteen thousand, twenty-seven".
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