Base | Representation |
---|---|
bin | 101101110110001011000… |
… | …000101001110000101010 |
3 | 102011012002202220211120221 |
4 | 231312023000221300222 |
5 | 403104303031411132 |
6 | 10411201203240254 |
7 | 443422253421163 |
oct | 55661300516052 |
9 | 12135082824527 |
10 | 3150543232042 |
11 | 100515757a128 |
12 | 42a71a67908a |
13 | 19b1307c012b |
14 | ac6b689476a |
15 | 56e45d7ae97 |
hex | 2dd8b029c2a |
3150543232042 has 4 divisors (see below), whose sum is σ = 4725814848066. Its totient is φ = 1575271616020.
The previous prime is 3150543232037. The next prime is 3150543232129. The reversal of 3150543232042 is 2402323450513.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 3136940441881 + 13602790161 = 1771141^2 + 116631^2 .
It is a junction number, because it is equal to n+sod(n) for n = 3150543231989 and 3150543232007.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 787635808009 + ... + 787635808012.
Almost surely, 23150543232042 is an apocalyptic number.
3150543232042 is a deficient number, since it is larger than the sum of its proper divisors (1575271616024).
3150543232042 is a wasteful number, since it uses less digits than its factorization.
3150543232042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1575271616023.
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 3150543232042 its reverse (2402323450513), we get a palindrome (5552866682555).
The spelling of 3150543232042 in words is "three trillion, one hundred fifty billion, five hundred forty-three million, two hundred thirty-two thousand, forty-two".
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