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315104005423 = 2631831197281
BaseRepresentation
bin1001001010111011010…
…10011000110100101111
31010010100010210000001101
410211131222120310233
520130313111133143
6400431244223531
731523366565514
oct4453552306457
91103303700041
10315104005423
111116a8aa6109
125109b83aba7
132393909161c
14113730bb30b
1582e36b9b4d
hex495da98d2f

315104005423 has 4 divisors (see below), whose sum is σ = 315105465888. Its totient is φ = 315102544960.

The previous prime is 315104005421. The next prime is 315104005451. The reversal of 315104005423 is 324500401513.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 315104005423 - 21 = 315104005421 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 315104005391 and 315104005400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315104005421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335458 + ... + 861823.

It is an arithmetic number, because the mean of its divisors is an integer number (78776366472).

Almost surely, 2315104005423 is an apocalyptic number.

315104005423 is a deficient number, since it is larger than the sum of its proper divisors (1460465).

315104005423 is a wasteful number, since it uses less digits than its factorization.

315104005423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1460464.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 315104005423 its reverse (324500401513), we get a palindrome (639604406936).

The spelling of 315104005423 in words is "three hundred fifteen billion, one hundred four million, five thousand, four hundred twenty-three".

Divisors: 1 263183 1197281 315104005423