Base | Representation |
---|---|
bin | 1001001010111011010… |
… | …10011000110101001011 |
3 | 1010010100010210000002102 |
4 | 10211131222120311023 |
5 | 20130313111133301 |
6 | 400431244224015 |
7 | 31523366565554 |
oct | 4453552306513 |
9 | 1103303700072 |
10 | 315104005451 |
11 | 1116a8aa6134 |
12 | 5109b83b00b |
13 | 23939091641 |
14 | 113730bb32b |
15 | 82e36b9b6b |
hex | 495da98d4b |
315104005451 has 2 divisors, whose sum is σ = 315104005452. Its totient is φ = 315104005450.
The previous prime is 315104005421. The next prime is 315104005459. The reversal of 315104005451 is 154500401513.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-315104005451 is a prime.
It is not a weakly prime, because it can be changed into another prime (315104005459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157552002725 + 157552002726.
It is an arithmetic number, because the mean of its divisors is an integer number (157552002726).
Almost surely, 2315104005451 is an apocalyptic number.
315104005451 is a deficient number, since it is larger than the sum of its proper divisors (1).
315104005451 is an equidigital number, since it uses as much as digits as its factorization.
315104005451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6000, while the sum is 29.
Adding to 315104005451 its reverse (154500401513), we get a palindrome (469604406964).
The spelling of 315104005451 in words is "three hundred fifteen billion, one hundred four million, five thousand, four hundred fifty-one".
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