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315115011145 = 511109193272347
BaseRepresentation
bin1001001010111100101…
…00010111110001001001
31010010100220111011001201
410211132110113301021
520130323420324040
6400432320144201
731523562254254
oct4453624276111
91103326434051
10315115011145
11111704232950
12510a3468061
132393b445b9c
141137474409b
1582e4640a9a
hex495e517c49

315115011145 has 32 divisors (see below), whose sum is σ = 418457255040. Its totient is φ = 225894666240.

The previous prime is 315115011137. The next prime is 315115011179. The reversal of 315115011145 is 541110511513.

It is not a de Polignac number, because 315115011145 - 23 = 315115011137 is a prime.

It is a super-2 number, since 2×3151150111452 (a number of 24 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1020862 + ... + 1293208.

It is an arithmetic number, because the mean of its divisors is an integer number (13076789220).

Almost surely, 2315115011145 is an apocalyptic number.

It is an amenable number.

315115011145 is a deficient number, since it is larger than the sum of its proper divisors (103342243895).

315115011145 is a wasteful number, since it uses less digits than its factorization.

315115011145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 272665.

The product of its (nonzero) digits is 1500, while the sum is 28.

Adding to 315115011145 its reverse (541110511513), we get a palindrome (856225522658).

The spelling of 315115011145 in words is "three hundred fifteen billion, one hundred fifteen million, eleven thousand, one hundred forty-five".

Divisors: 1 5 11 55 109 193 545 965 1199 2123 5995 10615 21037 105185 231407 272347 1157035 1361735 2995817 14979085 29685823 52562971 148429115 262814855 326544053 578192681 1632720265 2890963405 5729363839 28646819195 63023002229 315115011145