Base | Representation |
---|---|
bin | 101101110110101111010… |
… | …110110110101111000101 |
3 | 102011020200021100220001111 |
4 | 231312233112312233011 |
5 | 403112030134012013 |
6 | 10411341505325021 |
7 | 443443336555051 |
oct | 55665726665705 |
9 | 12136607326044 |
10 | 3151153032133 |
11 | 100543a810a47 |
12 | 42a86a936771 |
13 | 19b1c9c3a5a2 |
14 | ac73386cc61 |
15 | 56e7e68273d |
hex | 2ddaf5b6bc5 |
3151153032133 has 16 divisors (see below), whose sum is σ = 3308664324096. Its totient is φ = 2995354177200.
The previous prime is 3151153032091. The next prime is 3151153032221. The reversal of 3151153032133 is 3312303511513.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3151153032133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3151153032095 and 3151153032104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3151153062133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43268316 + ... + 43341082.
It is an arithmetic number, because the mean of its divisors is an integer number (206791520256).
Almost surely, 23151153032133 is an apocalyptic number.
It is an amenable number.
3151153032133 is a deficient number, since it is larger than the sum of its proper divisors (157511291963).
3151153032133 is a wasteful number, since it uses less digits than its factorization.
3151153032133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84504.
The product of its (nonzero) digits is 12150, while the sum is 31.
Adding to 3151153032133 its reverse (3312303511513), we get a palindrome (6463456543646).
The spelling of 3151153032133 in words is "three trillion, one hundred fifty-one billion, one hundred fifty-three million, thirty-two thousand, one hundred thirty-three".
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