Base | Representation |
---|---|
bin | 1001001010111111110… |
… | …11111001110101111111 |
3 | 1010010102210120000200221 |
4 | 10211133323321311333 |
5 | 20130402342322201 |
6 | 400435130002211 |
7 | 31524342042643 |
oct | 4453773716577 |
9 | 1103383500627 |
10 | 315142151551 |
11 | 11171858a937 |
12 | 510b0576367 |
13 | 23943c593b6 |
14 | 113781aac23 |
15 | 82e6c024a1 |
hex | 495fef9d7f |
315142151551 has 4 divisors (see below), whose sum is σ = 331728580600. Its totient is φ = 298555722504.
The previous prime is 315142151509. The next prime is 315142151573. The reversal of 315142151551 is 155151241513.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155151241513 = 127 ⋅1221663319.
It is a cyclic number.
It is not a de Polignac number, because 315142151551 - 211 = 315142149503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (315142151501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8293214496 + ... + 8293214533.
It is an arithmetic number, because the mean of its divisors is an integer number (82932145150).
Almost surely, 2315142151551 is an apocalyptic number.
315142151551 is a deficient number, since it is larger than the sum of its proper divisors (16586429049).
315142151551 is a wasteful number, since it uses less digits than its factorization.
315142151551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16586429048.
The product of its digits is 15000, while the sum is 34.
The spelling of 315142151551 in words is "three hundred fifteen billion, one hundred forty-two million, one hundred fifty-one thousand, five hundred fifty-one".
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