Base | Representation |
---|---|
bin | 11101010110011001… |
… | …101000101110001011 |
3 | 10000100021202221102002 |
4 | 131112121220232023 |
5 | 1004020132111133 |
6 | 22251045301215 |
7 | 2163645255035 |
oct | 352631505613 |
9 | 100307687362 |
10 | 31514332043 |
11 | 12402023117 |
12 | 613610480b |
13 | 2c8303496c |
14 | 174d5dcc55 |
15 | c46a54ce8 |
hex | 756668b8b |
31514332043 has 2 divisors, whose sum is σ = 31514332044. Its totient is φ = 31514332042.
The previous prime is 31514332019. The next prime is 31514332051. The reversal of 31514332043 is 34023341513.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31514332043 - 216 = 31514266507 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 31514331997 and 31514332015.
It is not a weakly prime, because it can be changed into another prime (31514332013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15757166021 + 15757166022.
It is an arithmetic number, because the mean of its divisors is an integer number (15757166022).
Almost surely, 231514332043 is an apocalyptic number.
31514332043 is a deficient number, since it is larger than the sum of its proper divisors (1).
31514332043 is an equidigital number, since it uses as much as digits as its factorization.
31514332043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 31514332043 its reverse (34023341513), we get a palindrome (65537673556).
The spelling of 31514332043 in words is "thirty-one billion, five hundred fourteen million, three hundred thirty-two thousand, forty-three".
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