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315145412003 is a prime number
BaseRepresentation
bin1001001011000000010…
…00010101110110100011
31010010110000200200012102
410211200020111312203
520130404211141003
6400435323521015
731524411542432
oct4454010256643
91103400620172
10315145412003
1111171a407524
12510b168916b
132394482b466
14113787b9119
1582e7148588
hex4960215da3

315145412003 has 2 divisors, whose sum is σ = 315145412004. Its totient is φ = 315145412002.

The previous prime is 315145411927. The next prime is 315145412011. The reversal of 315145412003 is 300214541513.

It is a strong prime.

It is an emirp because it is prime and its reverse (300214541513) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-315145412003 is a prime.

It is not a weakly prime, because it can be changed into another prime (315145412033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157572706001 + 157572706002.

It is an arithmetic number, because the mean of its divisors is an integer number (157572706002).

Almost surely, 2315145412003 is an apocalyptic number.

315145412003 is a deficient number, since it is larger than the sum of its proper divisors (1).

315145412003 is an equidigital number, since it uses as much as digits as its factorization.

315145412003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 315145412003 its reverse (300214541513), we get a palindrome (615359953516).

The spelling of 315145412003 in words is "three hundred fifteen billion, one hundred forty-five million, four hundred twelve thousand, three".