Base | Representation |
---|---|
bin | 100011110101000001101100… |
… | …0010110111110010001000001 |
3 | 1112022212011012112002022102122 |
4 | 1013222003120112332101001 |
5 | 312301414023423242121 |
6 | 3034134234551254025 |
7 | 123244630202404154 |
oct | 10752033026762101 |
9 | 1468764175068378 |
10 | 315151150212161 |
11 | 9146494135960a |
12 | 2b41a4a267a315 |
13 | 106b081a285553 |
14 | 57b757b74bc9b |
15 | 2667c10a565ab |
hex | 11ea0d85be441 |
315151150212161 has 2 divisors, whose sum is σ = 315151150212162. Its totient is φ = 315151150212160.
The previous prime is 315151150212121. The next prime is 315151150212253. The reversal of 315151150212161 is 161212051151513.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 303154064142400 + 11997086069761 = 17411320^2 + 3463681^2 .
It is a cyclic number.
It is not a de Polignac number, because 315151150212161 - 218 = 315151149950017 is a prime.
It is not a weakly prime, because it can be changed into another prime (315151150212121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157575575106080 + 157575575106081.
It is an arithmetic number, because the mean of its divisors is an integer number (157575575106081).
Almost surely, 2315151150212161 is an apocalyptic number.
It is an amenable number.
315151150212161 is a deficient number, since it is larger than the sum of its proper divisors (1).
315151150212161 is an equidigital number, since it uses as much as digits as its factorization.
315151150212161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 35.
The spelling of 315151150212161 in words is "three hundred fifteen trillion, one hundred fifty-one billion, one hundred fifty million, two hundred twelve thousand, one hundred sixty-one".
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