Base | Representation |
---|---|
bin | 101101110111001010111… |
… | …011100001101110100011 |
3 | 102011021212111211022100211 |
4 | 231313022323201232203 |
5 | 403114002100131433 |
6 | 10411455432354551 |
7 | 443460654564433 |
oct | 55671273415643 |
9 | 12137774738324 |
10 | 3151615630243 |
11 | 1005657951833 |
12 | 42a979845a57 |
13 | 19b271a28592 |
14 | ac77908a2c3 |
15 | 56eaa0ad8cd |
hex | 2ddcaee1ba3 |
3151615630243 has 2 divisors, whose sum is σ = 3151615630244. Its totient is φ = 3151615630242.
The previous prime is 3151615630181. The next prime is 3151615630253. The reversal of 3151615630243 is 3420365161513.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3151615630243 is a prime.
It is a super-3 number, since 3×31516156302433 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3151615630196 and 3151615630205.
It is not a weakly prime, because it can be changed into another prime (3151615630253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575807815121 + 1575807815122.
It is an arithmetic number, because the mean of its divisors is an integer number (1575807815122).
Almost surely, 23151615630243 is an apocalyptic number.
3151615630243 is a deficient number, since it is larger than the sum of its proper divisors (1).
3151615630243 is an equidigital number, since it uses as much as digits as its factorization.
3151615630243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 194400, while the sum is 40.
The spelling of 3151615630243 in words is "three trillion, one hundred fifty-one billion, six hundred fifteen million, six hundred thirty thousand, two hundred forty-three".
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